If the focal film distance changes from 8 inches to 16 inches, how is the intensity of the radiation beam affected?

Study for the DANB Radiology Exam. Prepare with flashcards and multiple choice questions, each question includes hints and explanations. Get ready for your exam!

When the focal film distance (FFD) is changed, the intensity of the radiation beam follows the inverse square law. This law states that the intensity of radiation is inversely proportional to the square of the distance from the source.

When the distance is doubled, as in changing from 8 inches to 16 inches, the intensity does not just reduce by half; rather, it decreases significantly because it is affected by the square of the distance change. Specifically, if the distance is increased by a factor of 2 (from 8 inches to 16 inches), the radiation intensity is reduced by a factor of 2 squared, which is 4.

Thus, when the FFD increases to 16 inches, the intensity of the radiation beam becomes one-quarter as intense compared to when it was at 8 inches. This understanding emphasizes the importance of distance in radiographic techniques and how it can greatly impact the exposure and quality of radiographic images.

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